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infix :

interval.infix :

(step_factor T)
 => 
interval T
Create an new interval with `step` multiplied by `step_factor`.

This is typically applied to an interval with implicit `step` of one,
e.g., in `2..10:2` will create "{2,4,6,8,10}".
Precondition
pre
  debug: ((step_factor.sign = 0): through=from)  # step cannot be zero unless from=through
  safety: (step *? step_factor).exists
0.095dev (GIT hash 09dff08de289bbb6f7136c7e2f8c66dcc1856bba)
last changed: 2026-04-16